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lintcode-medium-Jump Game

时间:2016-03-24 13:05:38      阅读:123      评论:0      收藏:0      [点我收藏+]

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Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

 

A = [2,3,1,1,4], return true.

A = [3,2,1,0,4], return false.

 

public class Solution {
    /**
     * @param A: A list of integers
     * @return: The boolean answer
     */
    public boolean canJump(int[] A) {
        // wirte your code here
        
        if(A == null || A.length == 0)
            return true;
        
        int max = 0;
        
        for(int i = 0; i <= max && i < A.length; i++){
            if(i + A[i] > max)
                max = i + A[i];
        }
        
        if(max >= A.length - 1)
            return true;
        else
            return false;
        
    }
}

 

lintcode-medium-Jump Game

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原文地址:http://www.cnblogs.com/goblinengineer/p/5314885.html

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