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Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
Your algorithm should run in O(n) complexity.
Given [100, 4, 200, 1, 3, 2]
,
The longest consecutive elements sequence is [1, 2, 3, 4]
. Return its length:4
.
public class Solution { /** * @param nums: A list of integers * @return an integer */ public int longestConsecutive(int[] num) { // write you code here if(num == null || num.length == 0) return 0; HashSet<Integer> set = new HashSet<Integer>(); for(int i = 0; i < num.length; i++) set.add(num[i]); int result = 1; for(int i = 0; i < num.length; i++){ int left = num[i] - 1; int right = num[i] + 1; int max = 1; while(set.contains(left)){ set.remove(left); left--; max++; } while(set.contains(right)){ set.remove(right); right++; max++; } result = Math.max(max, result); } return result; } }
lintcode-medium-Longest Consecutive Sequence
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原文地址:http://www.cnblogs.com/goblinengineer/p/5321898.html