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LeetCode Delete Node in a Linked List

时间:2016-03-28 02:02:53      阅读:125      评论:0      收藏:0      [点我收藏+]

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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

 

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这个题目要看清题意,是把函数参数中的这个节点删除,那样就很简单了,将其后继结点的值赋给这个结点,将后继结点的后继赋给这个结点的后继

 

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        node->val=node->next->val;
        node->next=node->next->next;
    }
};

 

LeetCode Delete Node in a Linked List

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原文地址:http://www.cnblogs.com/csudanli/p/5327570.html

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