Reverse Integer ---- LeetCode 007

class Solution {
public:
    int reverse(int x) 
    {
        int result = 0;
        while(x != 0)
        {
            if( x > 0 && result > (INT_MAX - x % 10) / 10 ||
                x < 0 && result < (INT_MIN - x % 10) / 10 )
                return 0;
            result = result * 10 + x % 10;
            x = x / 10;
        }
        return result;
    }
};