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Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
1 /** 2 * Definition for ListNode. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int val) { 7 * this.val = val; 8 * this.next = null; 9 * } 10 * } 11 */ 12 public class Solution { 13 /** 14 * @param head: The first node of linked list. 15 * @return: True if it has a cycle, or false 16 */ 17 public boolean hasCycle(ListNode head) { 18 if (head == null || head.next == null) { 19 return false; 20 } 21 ListNode slow = head; 22 ListNode fast = head.next; 23 while (fast != null && fast.next != null) { 24 slow = slow.next; 25 fast = fast.next.next; 26 if (fast == slow) { 27 return true; 28 } 29 } 30 return false; 31 } 32 }
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原文地址:http://www.cnblogs.com/FLAGyuri/p/5340086.html