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Linked List Cycle

时间:2016-03-31 10:53:08      阅读:130      评论:0      收藏:0      [点我收藏+]

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Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

 1 /**
 2  * Definition for ListNode.
 3  * public class ListNode {
 4  *     int val;
 5  *     ListNode next;
 6  *     ListNode(int val) {
 7  *         this.val = val;
 8  *         this.next = null;
 9  *     }
10  * }
11  */ 
12 public class Solution {
13     /**
14      * @param head: The first node of linked list.
15      * @return: True if it has a cycle, or false
16      */
17     public boolean hasCycle(ListNode head) {  
18         if (head == null || head.next == null) {
19              return false;
20         }
21         ListNode slow = head;
22         ListNode fast = head.next;
23         while (fast != null && fast.next != null) {
24             slow = slow.next;
25             fast = fast.next.next;
26             if (fast == slow) {
27                 return true;
28             }
29         }
30         return false;
31     }
32 }

 

Linked List Cycle

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原文地址:http://www.cnblogs.com/FLAGyuri/p/5340086.html

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