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时间:2016-03-31 21:41:48      阅读:275      评论:0      收藏:0      [点我收藏+]

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第一题、为printPrimes()方法画控制流程图:

 

技术分享
第二题、考虑测试用例t1=(n=3)和t2=(n=5)。即使这些测试用例游历printPrimes()方法中相同的主路径,他们不一定找出相同的错误。设计一个简单的错误,使得t2比t1更容易发现。

    数组越界问题

第三题、针对printPrimes(),找到一个测试用例,使得响应的测试路径访问连接while语句开始到for语句的边,而不用通过while循环体。

    t3=(n=0)(或者n=1)

第四题、针对printPrimes()的图例列举每个节点覆盖,边覆盖和主路径覆盖的测试需求。

           点覆盖:{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}

 

           边覆盖:{(1,2),(2,3),(2,12),(3,4),(4,5),(5,6),(6,7),(6,8),(7,5),(8,9), (5,9),(9,10),  (9,11),   (10,11),(11,2),(12,13),(13,14),(14,15),(15,13), (13,16)}

 

           主路径覆盖:{(1,2,3,4,5,6,7),

 

          (1,2,3,4,5,6,8,9,10,11),

 

          (1,2,3,4,5,6,8,9,11),

 

          (1,2,3,4,5,9,10,11),

 

          (1,2,3,4,5,9,11),  

 

          (1,2,12,13,14,15),

 

          (1,2,12,16),

 

          (3,4,5,6,8,9,10,11,2,12,13,14,15),

 

          (3,4,5,6,8,9,11,2,12,13,14,15),

 

          (3,4,5,6,8,9,10,11,2,12,13,16),

 

          (3,4,5,6,8,9,11,2,12,13,16),

 

          (3,4,5,9,10,11,2,12,13,14,15),

 

          (3,4,5,9,11,2,12,13,14,15),

 

          (3,4,5,9,10,11,2,12,13,16),

 

          (3,4,5,9,11,2,12,13,16),

 

          (6,7,5,9,10,11,2,12,13,14,15),

 

          (6,7,5,9,11,2,12,13,14,15),

 

          (6,7,5,9,10,11,2,12,13,16),

 

          (6,7,5,9,11,2,12,13,16),

 

          (14,15,13,16),

 

          (13,14,15,13),

 

          (5,6,7,5),

 

          (2,3,4,5,6,8,9,10,11,2),

 

          (2,3,4,5,6,8,9,11,2),

 

          (2,3,4,5,9,10,11,2),

 

          (2,3,4,5,9,11,2),

}

 

 

hm3

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原文地址:http://www.cnblogs.com/tjulinan/p/5342744.html

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