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之前机房没网就做的这道题,用的解析几何判断交点横坐标
#include<cmath> #include<cstdio> #include<cstring> #include<algorithm> #define N 500003 #define eps 1E-8 using namespace std; struct node { double k, b; int id; } line[N]; int n, stack[N], top = 0; bool ans[N]; inline bool cmp(node X, node Y) { if (fabs(X.k - Y.k) < eps) return X.b < Y.b; else return X.k < Y.k; } inline double crossx(int X, int Y) { return (line[Y].b - line[X].b) / (line[X].k - line[Y].k); } inline void insert(int x) { while (top) { if (fabs(line[x].k - line[stack[top]].k) < eps) --top; else if (crossx(x, stack[top]) <= crossx(stack[top], stack[top - 1]) && top > 1) --top; else break; } stack[++top] = x; } int main() { scanf("%d\n", &n); for(int i = 1; i <= n; ++i) { scanf("%lf%lf\n", &line[i].k, &line[i].b); line[i].id = i; } sort(line + 1, line + n + 1, cmp); for(int i = 1; i <= n; ++i) insert(i); for(int i = 1; i <= top; ++i) ans[line[stack[i]].id] = 1; for(int i = 1; i <= n; ++i) if (ans[i]) printf("%d ",i); return 0; }
hhh
【BZOJ 1007】【HNOI 2008】水平可见直线 解析几何
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原文地址:http://www.cnblogs.com/abclzr/p/5344786.html