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There are a row of n houses, each house can be painted with one of the three colors: red, blue or green. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color.
The cost of painting each house with a certain color is represented by a nx 3 cost matrix. For example, costs[0][0] is the cost of painting house0 with color red; costs[1][2] is the cost of painting house 1 with color green, and so on... Find the minimum cost to paint all houses.
All costs are positive integers.
Given costs = [[14,2,11],[11,14,5],[14,3,10]] return 10
house 0 is blue, house 1 is green, house 2 is blue, 2 + 5 + 3 = 10
public class Solution { /** * @param costs n x 3 cost matrix * @return an integer, the minimum cost to paint all houses */ public int minCost(int[][] costs) { // Write your code here if(costs == null || costs.length == 0) return 0; for(int i = 1; i < costs.length; i++){ costs[i][0] = costs[i][0] + Math.min(costs[i - 1][1], costs[i - 1][2]); costs[i][1] = costs[i][1] + Math.min(costs[i - 1][0], costs[i - 1][2]); costs[i][2] = costs[i][2] + Math.min(costs[i - 1][0], costs[i - 1][1]); } return Math.min(costs[costs.length - 1][0], Math.min(costs[costs.length - 1][1], costs[costs.length - 1][2])); } }
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原文地址：http://www.cnblogs.com/goblinengineer/p/5349739.html
