标签:des blog os io for art div ar
由于到达点时不能绕墙,因为这是无意义的,所以,两点间的最小墙依然是按照直线所穿过的墙计算。
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const double eps=0.000000001; struct point{ double x,y; }Point[100],des; struct edge{ point start,end; }Edge[100],Tmp; int ne,np; double multi(point p1,point p2, point p0){ return (p1.x-p0.x)*(p2.y-p0.y)-(p2.x-p0.x)*(p1.y-p0.y); } bool cross(edge v1, edge v2){ if(max(v1.start.x,v1.end.x)>=min(v2.start.x,v2.end.x)&& max(v2.start.x,v2.end.x)>=min(v1.start.x,v1.end.x)&& max(v1.start.y,v1.end.y)>=min(v2.start.y,v2.end.y)&& max(v2.start.y,v2.end.y)>=min(v1.start.y,v1.end.y)&& multi(v2.start,v1.end,v1.start)*multi(v1.end,v2.end,v1.start)>eps&& multi(v1.start,v2.end,v2.start)*multi(v2.end,v1.end,v2.start)>eps) return true; return false; } int main(){ while(scanf("%d",&ne)!=EOF){ np=0; for(int i=0;i<ne;i++){ scanf("%lf%lf",&Point[np].x,&Point[np].y); np++; scanf("%lf%lf",&Point[np].x,&Point[np].y); np++; Edge[i].start=Point[np-2]; Edge[i].end=Point[np-1]; } Point[np].x=0; Point[np].y=0; np++; Point[np].x=0; Point[np].y=100; np++; Point[np].x=100; Point[np].y=0; np++; Point[np].x=100; Point[np].y=100; np++; scanf("%lf%lf",&des.x,&des.y); int ans=1000,tmp; for(int i=0;i<np;i++){ Tmp.start=des; Tmp.end=Point[i]; tmp=0; for(int i=0;i<ne;i++){ if(cross(Tmp,Edge[i])) tmp++; } ans=min(ans,tmp); } printf("Number of doors = %d\n",ans+1); } }
标签:des blog os io for art div ar
原文地址:http://www.cnblogs.com/jie-dcai/p/3872805.html