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Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7357 Accepted Submission(s): 2552
题解:状态压缩bfs,比赛的时候无限me。。。。心中一万头草泥马奔腾。。。最后大家都说用状态压缩记录钥匙,,,瞬间感觉自己智商负无穷了。。。
其实也不难想,关键以前没怎么用状态压缩;当时想到了用vis存位置以及钥匙数,但是不知道怎么记录,为什么想不到状态压缩呐。。。要长记性了;
代码:
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<cmath> 5 #include<algorithm> 6 #include<queue> 7 using namespace std; 8 struct Node{ 9 int nx,ny,step; 10 //int key[11]; 11 int key; 12 }; 13 char mp[25][25]; 14 int vis[25][25][1025]; 15 int disx[4] = {0,0,1,-1}; 16 int disy[4] = {1,-1,0,0}; 17 int n,m,t; 18 void bfs(int sx,int sy){ 19 memset(vis,0,sizeof(vis)); 20 queue<Node>q; 21 Node a,b; 22 a.nx = sx;a.ny = sy; 23 a.step = 0; 24 //for(int i = 0;i < 11;i++)a.key[i] = 0; 25 a.key = 0; 26 vis[sx][sy][0] = 1; 27 q.push(a); 28 while(!q.empty()){ 29 a = q.front(); 30 q.pop(); 31 for(int i = 0; i < 4;i++){ 32 b.nx = a.nx + disx[i]; 33 b.ny = a.ny + disy[i]; 34 b.step = a.step + 1; 35 int x = b.nx, y = b.ny, step = b.step; 36 //for(int i = 0;i < 11;i++)b.key[i] = a.key[i]; 37 b.key = a.key; 38 if(x < 0 || y < 0 || x >= n || y >= m)continue; 39 if(mp[x][y] == ‘*‘)continue; 40 if(step >= t)continue; 41 if(mp[x][y] == ‘^‘){ 42 printf("%d\n",step); 43 return; 44 } 45 // if(vis[x][y] > 10)continue; 46 if(mp[x][y] >= ‘a‘ && mp[x][y] <= ‘j‘){ 47 //b.key[mp[x][y] - ‘a‘] = 1; 48 int p = 1 << (mp[x][y] - ‘a‘); 49 b.key |= p; 50 if(!vis[x][y][b.key]){ 51 vis[x][y][b.key] = 1; 52 q.push(b); 53 } 54 continue; 55 } 56 if(mp[x][y] >= ‘A‘ && mp[x][y] <= ‘J‘){ 57 //if(b.key[mp[x][y] - ‘A‘] == 0)continue; 58 int p = 1 << (mp[x][y] - ‘A‘); 59 if(b.key & p){ 60 if(!vis[x][y][b.key]){ 61 vis[x][y][b.key] = 1; 62 q.push(b); 63 } 64 } 65 continue; 66 } 67 if(!vis[x][y][b.key]){ 68 vis[x][y][b.key] = 1; 69 q.push(b); 70 } 71 } 72 } 73 puts("-1"); 74 return; 75 } 76 int main(){ 77 while(~scanf("%d%d%d",&n,&m,&t)){ 78 int sx,sy; 79 for(int i = 0;i < n; i++){ 80 scanf("%s",mp[i]); 81 for(int j = 0;j < m; j++){ 82 if(mp[i][j] == ‘@‘){ 83 sx = i; 84 sy = j; 85 } 86 } 87 } 88 mp[sx][sy] = ‘.‘; 89 bfs(sx,sy); 90 } 91 return 0; 92 }
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原文地址:http://www.cnblogs.com/handsomecui/p/5357168.html