hdu 1130(卡特兰数,大数)

时间：2016-04-08 11:39:26 阅读：177 评论：0 收藏：0 [点我收藏+]

标签：

How Many Trees?

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3382 Accepted Submission(s): 1960

Problem Description

A binary search tree is a binary tree with root k such that any node v reachable from its left has label (v) <label (k) and any node w reachable from its right has label (w) > label (k). It is a search structure which can find a node with label x in O(n log n) average time, where n is the size of the tree (number of vertices).

Given a number n, can you tell how many different binary search trees may be constructed with a set of numbers of size n such that each element of the set will be associated to the label of exactly one node in a binary search tree?

Input

The input will contain a number 1 <= i <= 100 per line representing the number of elements of the set.

Output

You have to print a line in the output for each entry with the answer to the previous question.

Sample Input

1
2
3

Sample Output

1
2
5

题意：由 n个结点组成，且左节点小于父节点 右结点大于父节点的树的种数

卡特兰数+BigInteger

import java.math.BigInteger;
import java.util.Scanner;

 
public class Main {
    public static void main(String[] args) {
        BigInteger [] h = new BigInteger[101];
        h[1] = new BigInteger("1");
        for(int i=2;i<=100;i++){
            h[i] = h[i-1].multiply(BigInteger.valueOf(4*i-2)).divide(BigInteger.valueOf(i+1));
        }
        Scanner sc =new Scanner (System.in);
        while(sc.hasNext()){
            int n =sc.nextInt();
            System.out.println(h[n]);
        }
    }
}
 

hdu 1130(卡特兰数,大数)

标签：

原文地址：http://www.cnblogs.com/liyinggang/p/5367259.html

踩

(0)

评论一句话评论（0）

分享档案

更多>

2021年07月29日 (22)
2021年07月28日 (40)
2021年07月27日 (32)
2021年07月26日 (79)
2021年07月23日 (29)
2021年07月22日 (30)
2021年07月21日 (42)
2021年07月20日 (16)
2021年07月19日 (90)
2021年07月16日 (35)

周排行