标签:des style blog color os io 2014 for
题目不附了。。
做法:这题真是比NOI2011的内题还要水。。不过蒟蒻我只能想到nlom的做法,据说有o(n)的做法,真是神。。
统计每个数的每一位的二进制位,然后对每一位用0或1试,如果答案都是1,则保留0(尽量小)
一次AC。
Codes:
1 #include<set> 2 #include<queue> 3 #include<cstdio> 4 #include<cstdlib> 5 #include<cstring> 6 #include<iostream> 7 #include<algorithm> 8 using namespace std; 9 const int N = 100100; 10 #define For(i,n) for(int i=1;i<=n;i++) 11 #define Rep(i,l,r) for(int i=l;i<=r;i++) 12 #define Down(i,r,l) for(int i=r;i>=l;i--) 13 struct ope{ 14 int kind,v; 15 }A[32][N]; 16 char op[5]; 17 int pows[32],Yuan,n,m,val; 18 19 void doit(int kth,int v){ 20 int tot = 0 , kind; 21 if(op[0]==‘A‘) kind = 1; 22 if(op[0]==‘O‘) kind = 2; 23 if(op[0]==‘X‘) kind = 3; 24 while(v){ 25 A[tot][kth].kind = kind;A[tot][kth].v = v % 2; 26 v/=2;tot++; 27 } 28 Rep(i,tot,30) A[i][kth].kind = kind; 29 } 30 31 void init(){ 32 scanf("%d%d",&n,&m); 33 pows[0] = 1; 34 For(i,30) pows[i] = pows[i-1] * 2; 35 For(i,n){ 36 scanf("\n"); 37 scanf("%s %d",&op,&val); 38 doit(i,val); 39 } 40 } 41 42 int Check(int kth,int M){ 43 For(i,n){ 44 if(A[kth][i].kind==1) M = M & A[kth][i].v; 45 if(A[kth][i].kind==2) M = M | A[kth][i].v; 46 if(A[kth][i].kind==3) M = M ^ A[kth][i].v; 47 } 48 return M; 49 } 50 51 void Work(){ 52 int ans = 0; 53 Down(i,30,0){ 54 if(Check(i,0)==1) { 55 ans+=pows[i]; 56 } 57 else{ 58 if(Yuan+pows[i]<=m){ 59 if(Check(i,1)==1){ 60 ans+=pows[i]; 61 Yuan+=pows[i]; 62 } 63 } 64 } 65 } 66 printf("%d\n",ans); 67 } 68 69 int main(){ 70 freopen("sleep.in","r",stdin); 71 freopen("sleep.out","w",stdout); 72 init(); 73 Work(); 74 return 0; 75 }
NOI2014 Day1_T1 起床困难综合症,布布扣,bubuko.com
标签:des style blog color os io 2014 for
原文地址:http://www.cnblogs.com/kjerome/p/3873051.html