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HDU 1016 Prime Ring Problem

时间:2016-04-08 17:59:56      阅读:114      评论:0      收藏:0      [点我收藏+]

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Prime Ring Problem

Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 39699    Accepted Submission(s): 17495


Problem Description
A ring is compose of n circles as shown in diagram. Put natural number 1, 2, ..., n into each circle separately, and the sum of numbers in two adjacent circles should be a prime.

Note: the number of first circle should always be 1.

技术分享
 

 

Input
n (0 < n < 20).
 

 

Output
The output format is shown as sample below. Each row represents a series of circle numbers in the ring beginning from 1 clockwisely and anticlockwisely. The order of numbers must satisfy the above requirements. Print solutions in lexicographical order.

You are to write a program that completes above process.

Print a blank line after each case.
 

 

Sample Input
6
8
 

 

Sample Output
Case 1:
1 4 3 2 5 6
1 6 5 2 3 4
 
Case 2:
1 2 3 8 5 6 7 4
1 2 5 8 3 4 7 6
1 4 7 6 5 8 3 2
1 6 7 4 3 8 5 2
 

 

Source
 
 
 
解析:DFS。
 
 
 
 1 #include <cstdio>
 2 #include <cstring>
 3 
 4 int n;
 5 bool pri[40] = {0,0,1,1,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1,0,1,0,0,0,0,0,1,0,0};
 6 int a[25];
 7 bool vis[25];
 8 
 9 void dfs(int level)
10 {
11     if(level == n && pri[a[1]+a[n]]){
12         for(int i = 1; i<n; ++i){
13             printf("%d ",a[i]);
14         }
15         printf("%d\n",a[n]);
16         return;
17     }
18     for(int i = 2; i <= n; ++i){
19         if(!vis[i] && pri[i+a[level]]){
20             a[++level] = i;
21             vis[i] = true;
22             dfs(level);
23             vis[i] = false;
24             --level;
25         }
26     }
27 }
28 
29 int main()
30 {
31     memset(vis,0,sizeof(vis));
32     int cnt = 0;
33     while(~scanf("%d",&n)){
34         printf("Case %d:\n",++cnt);
35         a[1] = 1;
36         dfs(1);
37         printf("\n");
38     }
39     return 0;
40 }

 

HDU 1016 Prime Ring Problem

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原文地址:http://www.cnblogs.com/inmoonlight/p/5369125.html

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