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Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3885 Accepted Submission(s):
1559
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #define M 1005 5 #define MAX 1000000 6 using namespace std; 7 int map[M][M],dis[M][M]; 8 int n; 9 10 void floyd() 11 { 12 int i,j,k; 13 int ans=MAX; 14 for(k=1; k<=n; k++) 15 { 16 for(i=1; i<k; i++) 17 for(j=i+1; j<k; j++) 18 if(ans>map[i][k]+map[k][j]+dis[j][i]) //注意这里的写法 19 ans=map[i][k]+map[k][j]+dis[j][i]; 20 for(i=1; i<=n; i++) 21 for(j=1; j<=n; j++) 22 if(dis[i][j]>dis[i][k]+dis[k][j]) 23 dis[i][j]=dis[i][k]+dis[k][j]; 24 } 25 if(ans<MAX) 26 printf("%d\n",ans); 27 else 28 printf("It‘s impossible.\n"); 29 } 30 31 int main() 32 { 33 int m,i,j; 34 while(~scanf("%d%d",&n,&m)) 35 { 36 for(i=1; i<=n; i++) 37 for(j=1; j<=n; j++) 38 { 39 if(i==j) map[i][j]=dis[i][j]=0; 40 else map[i][j]=dis[i][j]=MAX; 41 } 42 int a,b,c; 43 while(m--) 44 { 45 scanf("%d%d%d",&a,&b,&c); 46 if(map[a][b]>c) 47 map[a][b]=map[b][a]=dis[a][b]=dis[b][a]=c; 48 } 49 floyd(); 50 } 51 return 0; 52 }
hdu 1599 find the mincost route(无向图的最小环)
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原文地址:http://www.cnblogs.com/pshw/p/5371946.html