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Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
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Code:
class Solution {
public:
int singleNumber(vector<int>& nums) {
int ret = 0;
int mask = 1;
while(mask)
{
int countOne = 0; //number of digit 1
for(int i = 0; i < nums.size(); i ++)
{
if(nums[i] & mask)
countOne ++;
}
if(countOne % 3 == 1)
ret |= mask;
mask <<= 1;
}
return ret;
}
};
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原文地址：http://www.cnblogs.com/Alex0111/p/5373811.html
