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HDOJ 1339 A Simple Task(简单数学题,暴力)

时间:2016-04-10 15:01:21      阅读:197      评论:0      收藏:0      [点我收藏+]

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Problem Description
Given a positive integer n and the odd integer o and the nonnegative integer p such that n = o2^p.

Example

For n = 24, o = 3 and p = 3.

Task

Write a program which for each data set:

reads a positive integer n,

computes the odd integer o and the nonnegative integer p such that n = o2^p,

writes the result.

Input
The first line of the input contains exactly one positive integer d equal to the number of data sets, 1 <= d <= 10. The data sets follow.

Each data set consists of exactly one line containing exactly one integer n, 1 <= n <= 10^6.

Output
The output should consists of exactly d lines, one line for each data set.

Line i, 1 <= i <= d, corresponds to the i-th input and should contain two integers o and p separated by a single space such that n = o2^p.

Sample Input
1
24

Sample Output
3 3

思路:
就是一个公式: n = o*2^p.
n是输入的,o和p是我们需要求的。
需要注意的是o必须是奇数!
0<=p的。

import java.util.Scanner;

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();
        while(t-->0){
            int n = sc.nextInt();
            int a=0;
            int o=0;
            for(int p=0;p<n;p++){
                a=(int)Math.pow(2, p);
                if(a>n){
                    break;
                }
                if(n%a==0){
                    o=n/a;
                    if(o%2==0){
                        continue;
                    }
                    a=p;
                    break;
                }
            }
            System.out.println(o+" "+a);
        }

    }

}

HDOJ 1339 A Simple Task(简单数学题,暴力)

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原文地址:http://blog.csdn.net/qq_26525215/article/details/51105017

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