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费用流裸体......比赛的时候少写了一句话....导致增加了很多无用的边一直在TLE
#include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; const int maxn=500+10; int n; int belong[maxn]; int cost[maxn]; int g[maxn][maxn]; char str[maxn]; const int INF=0x7FFFFFFF; struct Edge { int from,to,cap,flow,cost; }; int N,M,K,len,s,t; vector<Edge> edges; vector<int> G[maxn]; int inq[maxn]; int d[maxn]; int p[maxn]; int a[maxn]; int use[maxn]; int dis[maxn][maxn]; void init() { for(int i=0; i<maxn; i++) G[i].clear(); edges.clear(); } void Addedge(int from,int to,int cap,int cost) { edges.push_back((Edge) { from,to,cap,0,cost }); edges.push_back((Edge) { to,from,0,0,-cost }); len=edges.size(); G[from].push_back(len-2); G[to].push_back(len-1); } bool BellmanFord(int s,int t,int &flow,int &cost) { for(int i=0; i<maxn; i++) d[i]=INF; memset(inq,0,sizeof(inq)); memset(p,-1,sizeof(p)); d[s]=0; inq[s]=1; p[s]=0; a[s]=INF; queue<int>Q; Q.push(s); while(!Q.empty()) { int u=Q.front(); Q.pop(); inq[u]=0; for(int i=0; i<G[u].size(); i++) { Edge& e=edges[G[u][i]]; if(e.cap>e.flow&&d[e.to]>d[u]+e.cost) { d[e.to]=d[u]+e.cost; p[e.to]=G[u][i]; a[e.to]=min(a[u],e.cap-e.flow); if(!inq[e.to]) { Q.push(e.to); inq[e.to]=1; } } } } if(d[t]==INF) return false; flow+=a[t]; cost+=d[t]*a[t]; int u=t; while(u!=s) { edges[p[u]].flow+=a[t]; edges[p[u]^1].flow-=a[t]; u=edges[p[u]].from; } return true; } void Mincost (int s,int t) { int flow=0,cost=0; while(BellmanFord(s,t,flow,cost)); printf("%d ",flow); printf("%d\n",2*flow-cost); } void read() { scanf("%s",str); for(int i=0;str[i];i++) belong[i+1]=str[i]-‘0‘; scanf("%s",str); for(int i=0;str[i];i++) cost[i+1]=str[i]-‘0‘; memset(g,0,sizeof g); for(int i=1;i<=n;i++) { int num; scanf("%d",&num); while(num--) { int id; scanf("%d",&id); g[i][id]=g[id][i]=1; } } } int main() { int T; scanf("%d",&T); while(T--) { scanf("%d",&n); s=0,t=n+1; init(); read(); for(int i=1;i<=n;i++) { if(belong[i]==0) Addedge(0,i,1,0); else Addedge(i,n+1,1,0); } for(int i=1;i<=n;i++) { if(belong[i]==1) continue; for(int j=1;j<=n;j++) { if(i==j) continue; if(g[i][j]==1) continue; if(belong[j]==0) continue; Addedge(i,j,1,cost[i]+cost[j]); } } Mincost(s,t); for(int i=0;i<edges.size();i=i+2) { if(edges[i].from==0) continue; if(edges[i].to==n+1) continue; if(edges[i].flow==0) continue; printf("%d %d\n",edges[i].from,edges[i].to); } } return 0; }
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原文地址:http://www.cnblogs.com/zufezzt/p/5375373.html