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2602 Bone Collector dp-3

时间:2016-04-11 22:22:12      阅读:231      评论:0      收藏:0      [点我收藏+]

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Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
技术分享
 

 

Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 

 

Output
One integer per line representing the maximum of the total value (this number will be less than 231).
 

 

Sample Input
1 5 10 1 2 3 4 5 5 4 3 2 1
 

 

Sample Output
14

 不知道为什么老是WA,以后再来研究吧

技术分享
 1 #include <iostream>
 2 #include <cstring>
 3 #include <algorithm>
 4 #include <cmath>
 5 using namespace std;
 6 
 7 int main()
 8 {
 9     int n,t,V,v[1005],w[1005],ans[1005];
10     cin>>t;
11     while(t--)
12     {
13         cin>>n>>V;
14         for(int i=0;i<n;i++)
15         cin>>v[i];
16         for(int i=0;i<n;i++)
17         cin>>w[i];
18         memset(ans,0,sizeof(ans));
19         for(int i=0;i<n;i++)
20         {
21             for(int j=V;j>=v[i];j--)
22             if(ans[j]<ans[j-v[i]]+w[i])
23             ans[j]=ans[j-v[i]]+w[i];
24         }
25         cout<<ans[V]<<endl;
26     }
27     return 0;
28 }
View Code

参考

http://www.cnblogs.com/yangcl/archive/2011/11/07/2240377.html

2602 Bone Collector dp-3

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原文地址:http://www.cnblogs.com/wang-ya-wei/p/5380222.html

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