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It‘s more of a brain-teaser than a Game Theory problem..
#!/bin/python3 T = int(input().strip()) for a0 in range(T): n = int(input().strip()) # # The last left 2 blocks can always produce a winning state, given % 3: # Think about the below cases # equal: 0-0 1-1 2-1 # non-equal: 0-1, 1-2, 0-2 if n == 1: print ("Kitty") elif n & 1: print ("Katty") else: print ("Kitty")
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原文地址：http://www.cnblogs.com/tonix/p/5394853.html
