标签:style blog color io art div ar line
A very interesting numeric problem. It involves a lot tricks.
Linear search (by +\-) is not feasible - too slow. So binary search is a good idea. Also please take special care of integer overflow!
class Solution { public: unsigned long _divide(unsigned long tgt, unsigned long adiv, unsigned long start) { if ((tgt - start) <= adiv) return (tgt - start) / adiv; unsigned n = 0; while (((adiv << n) + start) < tgt) n++; return (1 << (n - 1)) + _divide(tgt, adiv, (adiv << (n - 1)) + start); } int divide(int dividend, int divisor) { if (dividend == 0) return 0; unsigned long adend = abs(dividend); unsigned long adiv = abs(divisor); int iNeg = 0; if ((dividend < 0 && divisor > 0) || (dividend > 0 && divisor < 0)) { iNeg = -1; } else { iNeg = 1; } if (adiv == 1) return adend * iNeg; unsigned long ret = _divide(adend, adiv, 0); return ret * iNeg; } };
LeetCode "Divide Two Integers",布布扣,bubuko.com
LeetCode "Divide Two Integers"
标签:style blog color io art div ar line
原文地址:http://www.cnblogs.com/tonix/p/3875211.html