码迷,mamicode.com
首页 > 其他好文 > 详细

11. Container With Most Water

时间:2016-04-16 13:46:30      阅读:196      评论:0      收藏:0      [点我收藏+]

标签:

Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

 

Similar: 42. Trapping Rain Water

 

 1 public class Solution {
 2     public int maxArea(int[] height) {
 3         if (height.length < 2) return 0;
 4         int l = 0, r = height.length-1;
 5         int max = 0;
 6         while (l < r) {
 7             int lomax = height[l];
 8             int himax = height[r];
 9             max = Math.max(max, (r - l) * (lomax < himax ? lomax : himax));
10             
11             if (height[l] < height[r])
12                 while (l < r && height[l] <= lomax) l++; // will change l at least one step
13             else while (l < r && height[r] <= himax) r--;
14         }
15         
16         return max;
17     }
18 }

 

11. Container With Most Water

标签:

原文地址:http://www.cnblogs.com/joycelee/p/5398059.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!