码迷,mamicode.com
首页 > 其他好文 > 详细

6. ZigZag Conversion

时间:2016-04-16 15:26:12      阅读:106      评论:0      收藏:0      [点我收藏+]

标签:

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

代码如下:

public class Solution {
    public String convert(String s, int numRows) {
       int[] aa=new int[s.length()];
         char[] sa=new char[s.length()];
         char[] ss=s.toCharArray();
                int m=0;
    
         if(s.length()<=numRows||numRows<=1)
         return s;
         else{
           int n=1;
             for(int i=0;i<s.length();)
             {
                 while(n<=numRows&&i<s.length())
                     aa[i++]=n++;
              
                 int nn=numRows-1;
                 while(nn>0&&i<s.length())
                     aa[i++]=nn--;
 
                 if(nn==0)
                 n=2;
             }
            
            for(int j=1;j<=numRows;j++)
                 for(int k=0;k<s.length();k++)
                     if(aa[k]==j)
                     sa[m++]=ss[k];
 
         }
        
    return String.valueOf(sa);
}
}

6. ZigZag Conversion

标签:

原文地址:http://www.cnblogs.com/ghuosaao/p/5398349.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!