在字符串中找出连续最长的数字串

package com.oj5;

import java.util.Scanner;

public class Main {
	
    public static void main(String[] args) {
    	Scanner in = new Scanner(System.in);
    	String str = in.nextLine();
    	int[] length = new int[str.length()];
    	int[] begin = new int[str.length()];
    	int pos = 0;
    	
    	int count = 0;
    	boolean beginflag = false;
    	for(int i = 0;i < str.length(); i++)
    		if(str.charAt(i)<=‘9‘&&str.charAt(i)>=‘0‘&&beginflag==false){
    			beginflag = true;
    			count++;
    			begin[pos] = i;
    		}else if(str.charAt(i)<=‘9‘&&str.charAt(i)>=‘0‘){
    			count++;
    		}else if(beginflag==true&&(str.charAt(i)<‘0‘||str.charAt(i)>‘9‘)){
    			length[pos++] = count;
    			count = 0;
    			beginflag = false;
    		}
    	if(beginflag==true)
    		length[pos++] = count;
    	
    	int max = 0;
    	for(int i = 0;i < pos; i++)
    		if(length[i]>max)
    			max = length[i];
    	if(max==0){
    		System.out.println(0);
    		return ;
    	}
    	
    	for(int i = 0;i < pos; i++)
    		if(length[i]==max){
    			for(int j = begin[i];j < begin[i]+length[i]; j++)
    				System.out.print(str.charAt(j));
    			System.out.print(",");
    		}
    	System.out.print(max+"\n");
    	
    }
}