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136. Single Number

时间:2016-04-19 13:56:34      阅读:140      评论:0      收藏:0      [点我收藏+]

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Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

 

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1 public class Solution {
2     public int singleNumber(int[] nums) {
3         int ret = nums[0];
4         for (int i = 1; i < nums.length; i++) {
5             ret ^= nums[i];
6         }
7         return ret;
8     }
9 }

 

136. Single Number

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原文地址:http://www.cnblogs.com/joycelee/p/5407706.html

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