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Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next()
will return the next smallest number in the BST.
Note: next()
and hasNext()
should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class BSTIterator { vector<int> v; int pos; public: BSTIterator(TreeNode *root) { pos = 0; stack<TreeNode*> s; TreeNode *p = root, *pre = NULL; while(p || !s.empty()) { while(p) { s.push(p); p = p->left; } if(!s.empty()) { p = s.top(); s.pop(); v.push_back(p->val); p = p->right; } } } /** @return whether we have a next smallest number */ bool hasNext() { return pos < v.size(); } /** @return the next smallest number */ int next() { return v[pos++]; } }; /** * Your BSTIterator will be called like this: * BSTIterator i = BSTIterator(root); * while (i.hasNext()) cout << i.next(); */
173. Binary Search Tree Iterator -- 迭代器
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原文地址:http://www.cnblogs.com/argenbarbie/p/5416517.html