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Longest Palindromic Substring 最长回文子串
Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring.
普通做法,动态规划O(N^2)是能直接出结果的,长度从小到大排列,可以边动规边记录最大值。
Shortest Palindrome 最短回文生成
Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation.
For example:
Given "aacecaaa"
, return "aaacecaaa"
.
Given "abcd"
, return "dcbabcd"
.
普通做法,即找到从头开始的最长的回文,复杂度为O(N^2);然后补齐。
事实上,找到以某个点为中心的最长回文子串的经典算法是 Manacher算法,复杂度为O(N),可求出以字符串中各个点为中心的子串。Manacher算法可参考http://blog.csdn.net/ggggiqnypgjg/article/details/6645824/
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原文地址:http://www.cnblogs.com/littletail/p/5372747.html