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一下午和一晚上都在刚这道题,各种错误都集齐了so sad 我的时间啊!!!
后缀数组就先做到这里吧,是在伤不起啊QAQ
出现了各种奇怪的错误,看了标算,然后乱改自己的代码,莫名其妙的改A了,后来发现用字符直接给int赋值会WA,必须一个字符先给另一个字符赋值,后者再给int赋值就能A(什么鬼)。后来加了一个(int)s[n]强制转换就简单地A了,评测时强制转换睡觉了吗?还是我rp太差,得多攒点rp
#include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N = 110005; int t1[N], t2[N], c[N]; void st(int *x, int *y, int *sa, int n, int m) { int i; for(i = 0; i < m; ++i) c[i] = 0; for(i = 0; i < n; ++i) ++c[x[y[i]]]; for(i = 1; i < m; ++i) c[i] += c[i - 1]; for(i = n - 1; i >= 0; --i) sa[--c[x[y[i]]]] = y[i]; } void mkhz(int *a, int *sa, int n, int m) { int *t, *x = t1, *y = t2, i, j, p; for(i = 0; i < n; ++i) x[i] = a[i], y[i] = i; st(x, y, sa, n, m); for(p = 1, j = 1; p < n; j <<= 1, m = p) { for(p = 0, i = n - j; i < n; ++i) y[p++] = i; for(i = 0; i < n; ++i) if (sa[i] >= j) y[p++] = sa[i] - j; st(x, y, sa, n, m); for(t = x, x = y, y = t, p = 1, x[sa[0]] = 0, i = 1; i < n; ++i) x[sa[i]] = y[sa[i]] == y[sa[i - 1]] && y[sa[i] + j] == y[sa[i - 1] + j] ? p - 1 : p++; } } void mkh(int *r, int *sa, int *rank, int *h, int n) { int i, j, k = 0; for(i = 1; i <= n; ++i) rank[sa[i]] = i; for(i = 1; i <= n; h[rank[i++]] = k) for(k ? --k : 0, j = sa[rank[i] - 1]; r[i + k] == r[j + k]; ++k); } bool vis[105]; char s[N]; int a[N], rank[N], sa[N], h[N], n, k, belong[105], sz, ci = 0, ans[N], ansnum; bool can(int num) { memset(vis, 0, sizeof(vis)); int cnt = 0, cont = 0; for(int i = 2; i <= n; ++i) if (h[i] >= num) { for(int j = 1; j <= k; ++j) { if (sa[i] > belong[j - 1] && sa[i] < belong[j]) cnt += (int)(!vis[j]), vis[j] = 1; if (sa[i - 1] > belong[j - 1] && sa[i - 1] < belong[j]) cnt += (int)(!vis[j]), vis[j] = 1; } } else { if (cnt > k / 2) ans[++cont] = sa[i - 1]; cnt = 0; memset(vis, 0, sizeof(vis)); } if (cnt > k / 2) ans[++cont] = sa[n - 1]; if (cont != 0) ansnum = cont; return cont; } int main() { belong[0] = - 1; while (scanf("%d", &k), k) { n = sz = 1; ansnum = 0; for(int i = 1; i <= k; ++i) { scanf("%s", s + n); for(; s[n] != ‘\0‘; ++n) a[n] = (int)s[n]; a[n] = ‘#‘ + i; belong[sz++] = n; ++n; } --n; mkhz(a, sa, n + 1, 400); mkh(a, sa, rank, h, n); int left = 1, right = n, mid; while (left <= right) { mid = (left + right) >> 1; if (can(mid)) left = mid + 1; else right = mid - 1; } if (ci) puts(""); ++ci; if (left == 1) puts("?"); else { for(int i = 1; i <= ansnum; ++i) { for(int j = ans[i]; j < ans[i] + left - 1; ++j) putchar(s[j]); puts(""); } } } return 0; }
没了==
【POJ 3294】Life Forms 不小于k个字符串中的最长子串
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原文地址:http://www.cnblogs.com/abclzr/p/5422954.html