码迷,mamicode.com
首页 > 其他好文 > 详细

ZzuliOJ 1877 蛤玮打扫教室(线段树)

时间:2016-04-23 18:26:00      阅读:289      评论:0      收藏:0      [点我收藏+]

标签:

题目链接:http://acm.zzuli.edu.cn/zzuliacm/problem.php?id=1877

#include "algorithm"
#include "iostream"
#include "cstring"
#include "cstdio"
#include "string"
#include "stack"
#include "cmath"
#include "queue"
#include "set"
#include "map"

#define lson l , m , rt << 1
#define rson m + 1 , r , rt << 1 | 1

typedef long long ll;
using namespace std;

const int inf=0x3f3f3f3f;
const int maxn=1e5+5;

int t,n,m;

struct node{
    int l,r;
}qujian[maxn];
bool ok[maxn];

int tree[maxn<<2];
int col[maxn<<2];

void pushUp(int rt)
{
    tree[rt] = min( tree[rt<<1] ,tree[rt<<1|1] );
}
void push_down(int rt)
{
    if(col[rt])
    {
        tree[rt<<1]+=col[rt];
        tree[rt<<1|1]+=col[rt];
        col[rt<<1]+=col[rt];
        col[rt<<1|1]+=col[rt];
        col[rt]=0;
    }
}
void build(int l,int r,int rt)
{
    col[rt]=0;
    if(l==r)
    {
        tree[rt]=0;
        return;
    }
    int m = (l+r)>>1;
    build(lson);
    build(rson);
    pushUp(rt);
}

void update(int L,int R,int l,int r,int rt)
{
    if(L<=l&&R>=r)
    {
        col[rt]++;
        tree[rt]++;
        return ;
    }
    push_down(rt);

    int m = (l+r)>>1;
    if(L<=m)update(L,R,lson);
    if(R>m)update(L,R,rson);
    pushUp(rt);
}
int query(int L,int R,int l,int r,int rt)
{
    if(L<=l && r<=R)
    {
        return tree[rt];
    }
    push_down(rt);
    int m = (l+r)>>1;
    int ret = inf;
    if(L<=m)ret = min(ret, query(L,R,lson));
    if(R>m)ret=min(ret, query(L,R,rson) );
    return ret;
}
int main()
{
    //freopen("in.txt","r",stdin);
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d",&n,&m);

        build(1,n,1);
        memset(ok,0,sizeof ok);

        int l,r;
        for(int i=0;i<m;++i)
        {
            scanf("%d%d",&l,&r);
            qujian[i].l=l;
            qujian[i].r=r;
            update(l,r,1,n,1);
        }
        int ans=0;
        for(int i=0;i<m;++i)
        {
            if( query(qujian[i].l,qujian[i].r,1,n,1 )>1 )
            {
                ok[i]=1;
                ans++;
            }
        }
        printf("%d\n",ans);
        bool first=1;
        for(int i=0;i<m;++i)
        {
            if( ok[i] )
            {
                if(first)
                {
                    printf("%d",i+1);
                    first=false;
                }
                else
                {
                    printf(" %d",i+1);
                }
            }
        }
        if(ans)printf("\n");

    }

    return 0;
}

 

ZzuliOJ 1877 蛤玮打扫教室(线段树)

标签:

原文地址:http://www.cnblogs.com/bruce27/p/5425101.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!