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The area |
| Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) |
| Total Submission(s): 1637 Accepted Submission(s): 1298 |
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Problem Description
Ignatius bought a land last week, but he didn‘t know the area of the land because the land is enclosed by a parabola and a straight line. The picture below shows the area. Now given all the intersectant points shows in the picture, can you tell Ignatius the area of the land?
Note: The point P1 in the picture is the vertex of the parabola.  |
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Input
The input contains several test cases. The first line
of the input is a single integer T which is the number of test cases. T test
cases follow.
Each test case contains three intersectant points which shows in the picture, they are given in the order of P1, P2, P3. Each point is described by two floating-point numbers X and Y(0.0<=X,Y<=1000.0). |
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Output
For each test case, you should output the area of the
land, the result should be rounded to 2 decimal places.
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Sample Input
2 5.000000 5.000000 0.000000 0.000000 10.000000 0.000000 10.000000 10.000000 1.000000 1.000000 14.000000 8.222222 |
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Sample Output
33.33 40.69 Hint
For float may be not accurate enough, please use double instead of float. |
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Author
Ignatius.L
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求定积分公式
#include <iostream> #include <algorithm> #include <stdlib.h> #include <stdio.h> #include <math.h> using namespace std; double a,b,c; double f(double x) { return 1.0/3*a*x*x*x+0.5*b*x*x+c*x; } int main() { double x1,y1,x2,y2,x3,y3; int n; cin>>n; while(n--) { cin>>x1>>y1>>x2>>y2>>x3>>y3; a=(y2-y1)/((x2-x1)*(x2-x1)); //顶点式求a b=-2*a*x1; //对称轴求b c=y1-a*x1*x1-b*x1; //一般式求c printf("%.2lf\n",f(x3)-f(x2)-(y3+y2)*(x3-x2)/2); //定积分 } return 0; }
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原文地址：http://www.cnblogs.com/Ritchie/p/5425301.html
