码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode 136

时间:2016-04-25 00:55:21      阅读:134      评论:0      收藏:0      [点我收藏+]

标签:

Single Number

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

 

1 public class Solution {
2     public int singleNumber(int[] nums) {
3         int result = 0;
4         for(int i = 0 ; i<nums.length ; i++ ){
5             result ^= nums[i];
6         }
7         return result;
8     }
9 }

 

LeetCode 136

标签:

原文地址:http://www.cnblogs.com/Juntaran/p/5428818.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!