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题目:
Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / 2 3 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
题目解答:使用递归的方式来处理这道题目,每到叶子节点,就进行一次输出。
代码如下:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<string> binaryTreePaths(TreeNode* root) {
if(root == NULL)
return res;
stringstream ss;
ss << root -> val;
if((root -> left == NULL) && (root -> right == NULL))
{
res.push_back(ss.str());
return res;
}
else
{
getPaths(root,ss.str());
}
return res;
}
void getPaths(TreeNode *root,string s)
{
if((root -> left == NULL) && (root -> right ==NULL))
{
res.push_back(s);
}
if(root -> left != NULL)
{
stringstream ss;
ss << s << "->" << root -> left -> val;
getPaths(root -> left , ss.str());
}
if(root -> right != NULL)
{
stringstream ss;
ss << s << "->" << root -> right -> val;
getPaths(root -> right , ss.str());
}
}
private:
vector<string> res;
};
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原文地址:http://www.cnblogs.com/CodingGirl121/p/5440096.html