第六章-数据结构入门

6.1 forest

#include<iostream>  
#include<stdio.h>  
#include<string>  
#include<algorithm>  
using namespace std;  

struct person  
{  
    int number;  
    int streng;//体力   
    int seat;//站位   
}per[10086];  

bool compare(const person &p1,const person &p2)  
{  
    return p1.seat < p2.seat;  
}  

int main()  
{  

    int i,j;  
    int n;  
    cin >> n;  
    for(i = 1; i <= n; i++)  
    {  
        cin >> per[i].streng;  
        per[i].seat = i;  
        per[i].number = i;  
    }  

    int head = 1;  
    int tail = n;  
    for(i = 1; i <= n; i++)  
    {  
        if(per[i].streng > per[head].streng)  
        {  
            per[i].seat = per[head].seat - 1;  
            head = i;  
        }  
        else  
        {  
            per[i].seat = per[tail].seat + 1;  
            tail = i;  
        }  
    }  

    sort(per+1,per+n+1,compare);  

    for(i = 1; i <= n; i++)  
        cout << per[i].number <<" ";  


    return 0;     
}   

6.2 queue1

#include<iostream>  
#include<stdio.h>  
#include<string>  
#include<algorithm>  
using namespace std;  

int arr[10086];  

int main()  
{  

    int i,j;  
    int n;  
    cin >> n;  

    int head= 0;  
    int len = 0;  
    string s;  
    int num;  
    for(i = 0; i < n; i++)  
    {  
        cin >> s;  
        if(s == "INSERT")  
        {  
            cin >> num;  
            arr[len++] = num;  
        }  

        else  
        {  
            if(head > len-1)  
                cout << "ERROR" <<endl;  
            else  
            {  
                cout << arr[head] <<endl;  
                head++;  
            }  
        }  
    }  

    return 0;     
}  

6.3 queue2

#include<iostream>  
#include<stdio.h>  
#include<string>  
#include<algorithm>  
using namespace std;  

struct person  
{  
    bool in;  
    int left;  
    int right;  
}per[100086];  

int main()  
{  
    int i,j;  
    int n;  
    cin >> n;  

    per[0].right = 1;  
    per[0].in = false;  

    per[1].left = 0;  
    per[1].right = n+1;  
    per[1].in = true;  

    per[n+1].in = false;  

    int num,op;  
    for(i = 2; i <= n; i++)  
    {     
        cin >> num >> op;   

        if(op == 0)  
        {     
            per[per[num].left].right = i;  
            per[i].left = per[num].left;  
            per[num].left = i;  
            per[i].right = num;  
            per[i].in = true;  
        }  
        else  
        {  
            per[per[num].right].left = i;  
            per[i].right = per[num].right;  
            per[num].right = i;  
            per[i].left = num;  
            per[i].in = true;  
        }  
    }  

    int m;  
    cin >> m;  
    for(i = 0; i < m; i++)  
    {  
        cin >> num;  
        per[num].in = false;  
    }  

    i = 0;  
    while(per[i].right < n+1)  
    {  
        if(per[per[i].right].in)  
            cout << per[i].right << " ";  
        i = per[i].right;  
    }  

    return 0;  
}  

6.4 power

#include<iostream>  
#include<cstdio>  
#include<string>  
#include<algorithm>  
#include<stack>  
using namespace std;  

stack<int> s;  
int main()  
{  

    int i,j;  
    int n,size;  
    cin >> n >> size;     
    int now= 0;  

    int num;      
    for(i = 0; i < n; i++)  
    {  
        cin >> num;  

        while(now < num)  
            s.push(++now);  

        if(s.size() > size)  
            break;  

        if(s.top() != num)  
            break;  

        else  
            s.pop();  
    }  

    if(i < n)  
        cout <<"ERROR " << num;  
    else  
        cout <<"OK";  

    return 0;  
}  

6.5 maze1

#include<iostream>  
#include<cstdio>  
#include<string>  
#include<algorithm>  
#include<queue>  
using namespace std;  

struct maze  
{  
    int x;  
    int y;  
}a,b;  

int vis[1010][1010];  
int sum[1010][1010];  
int step[4][2]={{0,1},{0,-1},{1,0},{-1,0}};   
queue<maze> que;  

int main()  
{  

    int i,j;  

    int n,m,t;  
    cin >> n >> m >> t;   //n行m列 t障碍物   
    int sx,sy;   //起始坐标   
    int fx,fy;   //终点坐标   
    cin >> sx >> sy >> fx >> fy;  

    int tx,ty;  
    for(i = 0; i < t; i++)  
    {  
        cin >> tx >> ty;  
        vis[tx][ty] = 1;  
    } //障碍物标记1  

    a.x = sx;  
    a.y = sy;  
    que.push(a);  

    sum[sx][sy] = 1;  

    while(!que.empty())  
    {  
        a = que.front();  
        que.pop();  

        if(a.x == fx && a.y == fy)  
        {  
            cout << sum[a.x][a.y];  
            return 0;  
        }  

        else  
        {  
            for(i = 0; i < 4; i++)  
            {  
                int X = a.x + step[i][0];  
                int Y = a.y + step[i][1];  
                //在图内且未访问   
                if(!vis[X][Y] && X > 0 && Y > 0 && X <= n && Y <= m)  
                {  
                    vis[X][Y] = 1;  
                    sum[X][Y] = sum[a.x][a.y] + 1;  

                    b.x = X;  
                    b.y = Y;  
                    que.push(b);  
                }  
            }  
        }  

    }  

    cout <<"-1";    
    return 0;  
}