标签:二分匹配
3 3 0 0 0 1 0 1 0 1 0 0
2
#include<stdio.h>
#include<string.h>
int map[105][105],vist[105],match[105],m;
int find(int i)
{
for(int j=1;j<=m;j++)
if(!vist[j]&&map[i][j])
{
vist[j]=1;
if(!match[j]||find(match[j]))
{
match[j]=i; return 1;
}
}
return 0;
}
int main()
{
int a,n;
while(scanf("%d",&n)>0&&n)
{
scanf("%d",&m);
memset(map,0,sizeof(map));
for(int i=1;i<=n;i++)
for(int j=1;j<=m;j++)
{
scanf("%d",&a);
if(a) map[i][j]=1;
}
int ans=0;
memset(match,0,sizeof(match));
for(int i=1;i<=n;i++)
{
memset(vist,0,sizeof(vist));
ans+=find(i);
}
printf("%d\n",ans);
}
}
hdu2119Matrix (二分匹配,最小顶点覆盖),布布扣,bubuko.com
标签:二分匹配
原文地址:http://blog.csdn.net/u010372095/article/details/38294641