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leetcode 100. Same Tree(递归)

时间:2016-04-30 06:36:56      阅读:124      评论:0      收藏:0      [点我收藏+]

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Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

简单的递归。

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(p==nullptr&&q==nullptr){
            return true;
        }
        else if(p==nullptr||q==nullptr){
            return false;
        }
        if(p->val==q->val){
            return isSameTree(p->left,q->left)&&isSameTree(p->right,q->right);
        }
        return false;
    }
};

 

leetcode 100. Same Tree(递归)

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原文地址:http://www.cnblogs.com/zywscq/p/5448032.html

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