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LeetCode-Same Tree

时间:2016-05-05 01:56:20      阅读:105      评论:0      收藏:0      [点我收藏+]

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Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

树的遍历很有可能要转化为递归的思路

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public boolean isSameTree(TreeNode p, TreeNode q) {
        if(p==null && q==null){
            return true;
        }
        else if(p!=null && q==null){
            return false;
        }
        else if(p==null && q!=null){
            return false;
        }
        else if(p.val != q.val){
            return false;
        }
        if(isSameTree(p.left, q.left) && isSameTree(p.right, q.right)){
            return true;
        }
        return false;
        
    }
}

 

LeetCode-Same Tree

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原文地址:http://www.cnblogs.com/incrediblechangshuo/p/5460401.html

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