标签：
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
这种merge两个List的题目。除了可以从头往后merge，也可以从后往前merge
public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n){
int i=m-1;
int j=n-1;
int tail=m+n-1;
while(i>=0 && j>=0){
if(nums1[i] >= nums2[j]){
nums1[tail]=nums1[i];
i--;
}
else{
nums1[tail]=nums2[j];
j--;
}
tail--;
}
if(i<0 && tail >=0){
for (int k=0; k<=tail; k++){
nums1[k]=nums2[k];
}
}
}
}
标签：
原文地址：http://www.cnblogs.com/incrediblechangshuo/p/5460396.html
