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2014多校联合4

时间:2014-07-31 00:07:05      阅读:301      评论:0      收藏:0      [点我收藏+]

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1002:Redraw Beautiful Drawings

最大流。。。。用sap+gap优化的模版过的。。。

1. 源点 -> 每一行对应的点,流量限制为该行的和

2. 每一行对应的点 -> 每一列对应的点,流量限制为 K

3. 每一列对应的点 -> 汇点,流量限制为该列的和

跑一遍最大流。

如果流量小于总权值和,那么说明impossible。

如果等于:

构建残图网络,如果残图网络可以形成一条回路,那么说明有多解。

#include <stdio.h>
#include <iostream>
#include <algorithm>
#include <string.h>
#include<queue>
using namespace std;
#define INF 99999999
const int maxn =810;
const int maxm =2*410*410+410*4;
const int oo = 1<<29;
struct Arclist
{
    int cnt, head[maxn], dis[maxn];
    int cur[maxn], pre[maxn], gap[maxn], aug[maxn];
    int mp[maxn][maxn];
    int vis[maxn];
    int vis2[maxn];
    struct node
    {
        int u, v, w, next;
    }edge[maxm];
    void init()
    {
        cnt = 0;
        memset(head,-1,sizeof(head));
    }
    void add(int u, int v, int w)
    {
        edge[cnt].u = u;
        edge[cnt].v = v;
        edge[cnt].w = w;
        edge[cnt].next = head[u];
        head[u] = cnt++;
        edge[cnt].u = v;
        edge[cnt].v = u;
        edge[cnt].w = 0;
        edge[cnt].next = head[v];
        head[v] = cnt++;
    }
    int sap(int s, int e, int n)
    {
        int max_flow = 0, u = s;
        int mindis;
        for(int i = 0; i <= n; i++)
        {
            cur[i] = head[i];
            dis[i] = 0;
            gap[i] = 0;
        }
        aug[s] = oo;
        pre[s] = -1;
        gap[0] = n;
        while(dis[s]<n)
        {
            bool flag = false;
            if(u==e)
            {
                max_flow += aug[e];
                for(int v = pre[e]; v != -1; v = pre[v])
                {
                    int id = cur[v];
                    edge[id].w -= aug[e];
                    edge[id^1].w += aug[e];
                    aug[v] -= aug[e];
                    if(edge[id].w==0) u = v;
                }
            }
            for(int id = cur[u]; id != -1; id = edge[id].next)
            {
                int v = edge[id].v;
                if(edge[id].w>0 && dis[u]==dis[v]+1)
                {
                    flag = true;
                    pre[v] = u;
                    cur[u] = id;
                    aug[v] = std::min(aug[u], edge[id].w);
                    u = v;
                    break;
                }
            }
            if(flag==false)
            {
                if(--gap[dis[u]]==0) break;
                mindis = n;
                cur[u] = head[u];
                for(int id = head[u]; id != -1; id = edge[id].next)
                {
                    int v = edge[id].v;
                    if(edge[id].w>0 && dis[v]<mindis)
                    {
                        mindis = dis[v];
                        cur[u] = id;
                    }
                }
                dis[u] = mindis+1;
                ++gap[dis[u]];
                if(u!=s) u = pre[u];
            }
        }
        return max_flow;
    }
    int n,m,k;
    int sou(int pre,int x,int leap)
    {
        vis2[x]=1;
        if(leap==0)
        {
            for(int i=n+1;i<=m+n;i++)
            {
                if(i==pre)continue;
                if(mp[x][i]==0)continue;
                if(vis2[i])
                {
                    vis2[x]=0;
                    return 1;
                }
                if(sou(x,i,1)){
                    vis2[x]=0;
                    return 1;
                }
            }
        }
        if(leap==1)
        {
            for(int i=1;i<=n;i++)
            {
                if(i==pre)continue;
                if(mp[x][i]==0)continue;
                if(vis2[i]){
                    vis2[x]=0;
                    return 1;
                }
                if(sou(x,i,0)){
                    vis2[x]=0;
                    return 1;
                }
            }
        }
        vis2[x]=0;
        return 0;
    }
    int dfs()
    {
       memset(vis,0,sizeof(vis));
       memset(vis2,0,sizeof(vis2));
       for(int i=1;i<=n;i++)
       {
           if(vis[i])continue;
           if(sou(-1,i,0))return 1;
       }
       return 0;
    }
    void pan()
    {
        memset(mp,0,sizeof(mp));
        for(int i=0;i<cnt;i++)
        {
            int u=edge[i].u;
            int v=edge[i].v;
            int w=edge[i].w;
            if(u>n)continue;
            if(v<=n||v>n+m)continue;
            mp[u][v]=w;
            mp[v][u]=k-w;
        }
        if(dfs())
        {
            cout<<"Not Unique"<<endl;
            return ;
        }
        cout<<"Unique"<<endl;
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=m;j++)
            {
                if(j!=1)cout<<" ";
                printf("%d",k-mp[i][j+n]);
            }
            cout<<endl;
        }
    }
}G;
int a[510];
int b[510];
int main()
{
    int m,n,k;
    while(~scanf("%d%d%d",&n,&m,&k))
    {
        int st=n+m+1;
        int ed=n+m+2;
        G.init();
        int ans=0;
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&a[i]);
            G.add(st,i,a[i]);
            ans+=a[i];
        }
        for(int i=n+1;i<=n+m;i++)
        {
            scanf("%d",&b[i]);
            G.add(i,ed,b[i]);
        }
        for(int i=1;i<=n;i++)
        {
            for(int j=n+1;j<=n+m;j++)
            {
                G.add(i,j,k);
            }
        }
        int mx;
        mx=G.sap(st,ed,n+m+2);
        if(mx<ans)cout<<"Impossible"<<endl;
        else
        {
            G.n=n;
            G.m=m;
            G.k=k;
            G.pan();
        }
    }
    return 0;
}

1003:Scary Path Finding Algorithm

由题意可知,直接构造就行。。。

#include <iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<stdlib.h>
#include<vector>
#include<cmath>
#include<queue>
#include<set>
using namespace std;
void dos()
{
    int a[31];
    a[0]=1;
    for(int i=1; i<=30; i++)
    {
        a[i]=a[i-1]*2;
    }
    int n=30*2+1;
    int m=30*3-3;
    cout<<n<<" "<<m<<endl;
    for(int i=1; i<=29; i++)
    {
        printf("%d %d %d\n",i,i+30,0);
        printf("%d %d %d\n",i,i+1,-a[30-i]);
        printf("%d %d %d\n",i+30,i+1,-a[30-i+1]);
    }
}
long long spfa_slf()
{
    int n,m;
    cin >> n >> m;

    vector<pair<int,int> > edges[111];
    for(int i = 0; i < m; i++)
    {
        int x,y,w;
        cin >> x >> y >> w;
        edges[x].push_back(make_pair(y,w));
    }

    deque<int> q;
    vector<long long> dist(n+1, ~0ULL>>1);
    vector<bool> inQueue(n+1, false);
    dist[1] = 0;
    q.push_back(1);
    inQueue[1] = true;

    int doge = 0;
    while(!q.empty())
    {
        int x = q.front();
        q.pop_front();
        if(doge++ > 23333333)
        {
            puts("doge");
            return 233;
        }
        for(vector<pair<int,int> >::iterator it = edges[x].begin();
                it != edges[x].end(); ++it)
        {
            int y = it->first;
            int w = it->second;
            if(dist[y] > dist[x] + w)
            {
                dist[y] = dist[x] + w;
                if(!inQueue[y])
                {
                    inQueue[y] = true;
                    if(!q.empty() && dist[y] > dist[q.front()])
                        q.push_back(y);
                    else
                        q.push_front(y);
                }
            }
        }
        inQueue[x] = false;
    }
    return dist[n];
}
int main()
{
    int n;
   // freopen("data.in","r",stdin);
    while(~scanf("%d",&n))
    {
        dos();
    }
   // spfa_slf();
   // cout<<"-00"<<endl;
    return 0;
}









2014多校联合4,布布扣,bubuko.com

2014多校联合4

标签:style   blog   color   os   io   for   2014   ar   

原文地址:http://blog.csdn.net/rowanhaoa/article/details/38307083

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