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Given a string s consists of upper/lower-case alphabets and empty space characters ‘
‘
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
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c++ code:
class Solution { public: int lengthOfLastWord(string s) { int tail = s.size() - 1; int cnt=0; while(tail>=0 && ' ' == s[tail]) tail--; while(tail>=0 && s[tail]!=' ') { cnt++; tail--; } return cnt; } };
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原文地址:http://blog.csdn.net/itismelzp/article/details/51331453