标签：
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
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c++ code:
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
if (0 == n) return;
if (0 == m)
for (int i = 0; i<n; i++) nums1[i] = nums2[i];
int k = m + n - 1;
int i = m - 1, j = n - 1;
while (i>=0 && j>=0)
{
if (nums1[i]>nums2[j]) nums1[k--] = nums1[i--];
else nums1[k--] = nums2[j--];
}
while (j >= 0) nums1[k--] = nums2[j--];
}
};标签：
原文地址：http://blog.csdn.net/itismelzp/article/details/51331470
