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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and
you are given the third node with value 3, the linked list should become 1
-> 2 -> 4 after calling your function.
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c++ code:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void deleteNode(ListNode* node) {
if(NULL == node) return;
ListNode *tmp = node->next;
node->val = tmp->val;
node ->next = tmp->next;
delete tmp;
}
};LeetCode:Delete Node in a Linked List
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原文地址：http://blog.csdn.net/itismelzp/article/details/51331359
