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Given an array of integers, every element appears twice except for one. Find that single one.
代码如下:
1 public class Solution { 2 public int singleNumber(int[] nums) { 3 if(nums.length==1) 4 return nums[0]; 5 6 Arrays.sort(nums); 7 int s=0; 8 for(int i=0;i<nums.length-1;) 9 { 10 if(nums[i]==nums[i+1]) 11 i=i+2; 12 else 13 {return nums[i]; } 14 } 15 16 return nums[nums.length-1]; 17 18 } 19 }
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原文地址:http://www.cnblogs.com/ghuosaao/p/5478999.html