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题目:给定一个数组和滑动窗口的大小,请找到所有滑动窗口里的最大值。例如,如果输入数组{2,3,4,2,6,2,5,1}及滑动窗口的大小3,那么一共存在6个滑动窗口,他们的最大值分别是{4,4,6,6,6,5},如图所示:
1 #include<iostream> 2 #include<vector> 3 #include<deque> 4 using namespace std; 5 6 vector<int> maxInWindows(const vector<int>& num,unsigned int size) 7 { 8 vector<int> MaxInWindows; 9 if(num.size()>size&&size>=1) 10 { 11 deque<int> index; 12 for(unsigned int i=0;i<size;++i) 13 { 14 while(!index.empty()&&num[i]>=num[index.back()]) 15 index.pop_back(); 16 index.push_back(i); 17 } 18 for(i=size;i<num.size();++i) 19 { 20 MaxInWindows.push_back(num[index.front()]); 21 while(!index.empty()&&num[i]>=num[index.back()]) 22 index.pop_back(); 23 if(!index.empty()&&index.front()<(int)(i-size)) 24 index.pop_front(); 25 index.push_back(i); 26 } 27 MaxInWindows.push_back(num[index.front()]); 28 } 29 return MaxInWindows; 30 } 31 32 void print(vector<int> result) 33 { 34 vector<int>::iterator ite; 35 for(ite=result.begin();ite!=result.end();++ite) 36 cout<<*ite<<" "; 37 cout<<endl; 38 result.clear(); 39 } 40 41 void main() 42 { 43 int ia[10]={1,2,3,4,5,6,7,8,9,10}; 44 vector<int> ib(ia,ia+10); 45 print(maxInWindows(ib,3)); 46 }
方法2:
1 #include<iostream> 2 #include<vector> 3 #include<deque> 4 using namespace std; 5 6 7 int searchmax(const vector<int>&num,unsigned int size) 8 { 9 int max=num[0]; 10 for(int i=1;i<size;i++) 11 { 12 if(num[i]>max) 13 max=num[i]; 14 } 15 return max; 16 } 17 18 vector<int> maxInWindows(vector<int>& num,unsigned int size) 19 { 20 vector<int> MaxInWindows; 21 int length=num.size(); 22 for(int i=0;i<length-size+1;i++) 23 { 24 MaxInWindows.push_back(searchmax(num,size)); 25 num.erase(num.begin()); 26 } 27 return MaxInWindows; 28 } 29 30 31 32 33 void print(vector<int> result) 34 { 35 vector<int>::iterator ite; 36 for(ite=result.begin();ite!=result.end();++ite) 37 cout<<*ite<<" "; 38 cout<<endl; 39 result.clear(); 40 } 41 42 void main() 43 { 44 int ia[10]={1,2,3,4,5,6,7,8,9,10}; 45 vector<int> ib(ia,ia+10); 46 print(maxInWindows(ib,3)); 47 print(ib); 48 }
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原文地址:http://www.cnblogs.com/wxdjss/p/5479189.html