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Time Limit: 12000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
#include<iostream> #include<cstdio> #include<cmath> #include<string> #include<queue> #include<algorithm> #include<stack> #include<cstring> #include<vector> #include<list> #include<set> #include<map> using namespace std; #define ll __int64 #define mod 1000000007 #define inf 999999999 //#pragma comment(linker, "/STACK:102400000,102400000") int scan() { int res = 0 , ch ; while( !( ( ch = getchar() ) >= ‘0‘ && ch <= ‘9‘ ) ) { if( ch == EOF ) return 1 << 30 ; } res = ch - ‘0‘ ; while( ( ch = getchar() ) >= ‘0‘ && ch <= ‘9‘ ) res = res * 10 + ( ch - ‘0‘ ) ; return res ; } ll a[110]; ll ji; ll ans,x,y; ll gcd(ll x,ll y) { return y==0?x:gcd(y,x%y); } void dfs(ll lcm,ll pos,ll step) { if(lcm>x) return; if(pos==ji) { if(step==0) return; if(step&1) ans+=x/lcm; else ans-=x/lcm; return; } dfs(lcm,pos+1,step); dfs(lcm/gcd(a[pos],lcm)*a[pos],pos+1,step+1); } int main() { ll z,i,t; while(~scanf("%I64d%I64d",&x,&y)) { x--; ji=0; for(i=0;i<y;i++) { scanf("%I64d",&z); if(z==0)continue; a[ji++]=z; } ans=0; dfs(1,0,0); printf("%I64d\n",ans); } return 0; }
hdu 1796 How many integers can you find 容斥定理
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原文地址:http://www.cnblogs.com/jhz033/p/5479946.html