标签:blog os io for div amp size type
就是判断一下是不是每一个课程都能找到自己的代表人,做一遍最大匹配看看匹配数是否等于p即可
#include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <climits> #include <string> #include <iostream> #include <map> #include <cstdlib> #include <list> #include <set> #include <queue> #include <stack> using namespace std; typedef long long LL; const int maxn = 400; int p,n,bx[maxn],by[maxn],vis[maxn]; bool g[maxn][maxn]; int dfs(int now) { for(int i = 1;i <= n;i++) if(g[now][i] && !vis[i]) { vis[i] = true; if(!by[i] || dfs(by[i])) { bx[now] = i; by[i] = now; return 1; } } return 0; } void solve() { memset(bx,0,sizeof(bx)); memset(by,0,sizeof(by)); //为每一门课程寻找代表 int ans = 0; for(int i = 1;i <= p;i++) { if(!bx[i]) { memset(vis,0,sizeof(vis)); ans += dfs(i); } } if(ans == p) puts("YES"); else puts("NO"); } int main() { int T; scanf("%d",&T); while(T--) { scanf("%d%d",&p,&n); memset(g,0,sizeof(g)); for(int i = 1;i <= p;i++) { int cnt; scanf("%d",&cnt); for(int j = 1;j <= cnt;j++) { int tmp; scanf("%d",&tmp); g[i][tmp] = true; } } solve(); } return 0; }
POJ 1469 COURSES 二分图最大匹配,布布扣,bubuko.com
标签:blog os io for div amp size type
原文地址:http://www.cnblogs.com/rolight/p/3880546.html