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Description
On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.
The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.
Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.
14
4 4
2
0 2
给我一个天数，问最少能过几个假期，最多能过几个假期~
分情况看余数~
讨论就好了
#include<stdio.h>
//#include<bits/stdc++.h>
#include<string.h>
#include<iostream>
#include<stack>
#include<math.h>
#include<map>
#include<sstream>
#include<set>
#include<queue>
#include<vector>
#include<algorithm>
#include<limits.h>
#define inf 0x3fffffff
#define LLL l,m,rt<<1
#define RRR r,m+1,rt<<1|1
using namespace std;
int main()
{
int n;
cin>>n;
if(n==1)
{
cout<<"0"<<" "<<"1"<<endl;
}
else if(2<=n&&n<=5)
{
cout<<"0"<<" "<<"2"<<endl;
}
else if(n==6)
{
cout<<"1"<<" "<<"2"<<endl;
}
else
{
int pot;
int pos;
pot=n/7*2;
pos=n/7*2;
if(n%7>=0&&n%7<=5)
{
cout<<pot<<" ";
}
else
{
cout<<pot+1<<" ";
}
if(n%7==1)
{
cout<<pos+1<<endl;
}
else if(n%7==0)
{
cout<<pos<<endl;
}
else
{
cout<<pos+2<<endl;
}
}
return 0 ;
}
Codeforces Round #350 (Div. 2) A
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原文地址：http://www.cnblogs.com/yinghualuowu/p/5480867.html
