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LeetCode:Missing Number

时间:2016-05-12 11:31:13      阅读:170      评论:0      收藏:0      [点我收藏+]

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Missing Number

Total Accepted: 50707 Total Submissions: 125920 Difficulty: Medium

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

For example,
Given nums = [0, 1, 3] return 2.

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.

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c++ code:

class Solution {
public:
    int missingNumber(vector<int>& nums) {
        int ret=0;
        for(int i=0;i<nums.size();i++)
            ret ^= (i+1) ^ nums[i];
        return ret;
    }
};


LeetCode:Missing Number

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原文地址:http://blog.csdn.net/itismelzp/article/details/51377969

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