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题意:输入n,有n个插座,下面n行是每个插座的类型(最后24个字母来表示一个插座,没有空格放心用scanf,但是有可能插座会相同,但是这个没有什么影响)
输入m,有m个电器,下面m行每行两个单词分别是电器的名字和插头类型(同样24个字母单词内没空格,两个单词空格隔开)
输入k,有k个转换器,下面k行每行两个单词,分别表示转换器的入口类型和插头类型
每种转换器的个数是无限的,转换器本身可以与转换器相连
要你求,让最多的电器能够插在插座上(可以用转换器辅助也可以直接插上去),输入不能插上去的电器的数量
#include <iostream> #include <cstdio> #include <string> #include <utility> #include <queue> #include <vector> //#define T using namespace std; const int infinity = 1000000000; int count = 0; struct Edge { int from,to, flow, capacity; Edge(const int &v,const int &a, const int &c,const int &f) { from=v,to = a, capacity = c,flow=f; } }; int vexnum, edgenum;//表示顶点个数和边个数 int receptacle, device, adapter;//表示插座数,电器数,转换器种类 vector<string>table_receptacle; vector<string>table_device; vector<pair<string,string> >table_adapter; int src, sink;//表示源点和汇点 int max_flow;//最大流 vector<Edge>edge;//边数的两倍 vector<vector<int> >adjList;//邻接表 void addEdge(const int& from, const int& to,const int& capacity) { edge.push_back(Edge(from,to,capacity,0)); adjList[from].push_back(edge.size()-1); edge.push_back(Edge(to,from,0,0)); adjList[to].push_back(edge.size()-1); } void init() { table_adapter.clear(); table_device.clear(); table_receptacle.clear(); edge.clear(); adjList.clear(); } void network() { max_flow = 0; src = 0;//源点设置成0 //接受插座 cin >> receptacle; table_receptacle.resize(1); for (int i = 0; i < receptacle; i++) { string type; cin >> type;//插座的类型 table_receptacle.push_back(type); } //接受电器 cin >> device; table_device.resize(1); for (int i = 0; i < device; i++) { string name, type; cin >> name >> type; table_device.push_back(type); } //接受适配器 cin >> adapter; table_adapter.resize(1); for (int i = 0; i < adapter; i++) { string type1, type2; cin >> type1 >> type2; table_adapter.push_back(make_pair(type1,type2)); } //初始化源点,汇点,邻接表,顶点数 src = 0, sink = device + receptacle + adapter+1, vexnum = 1 + sink; adjList.resize(vexnum); //连边 for (int i = 1; i<=device; i++) { addEdge(src, i, 1); for (int j = 1; j <= receptacle; j++) { if (table_device[i]== table_receptacle[j]) { addEdge(i, device + j, 1); } } for (int j = 1; j <= adapter; j++) { if (table_device[i] == table_adapter[j].first) { addEdge(i, device + receptacle + j, infinity); } } } for (int i = 1; i <= receptacle; i++) { addEdge(device + i, sink, 1); for (int j = 1; j <= adapter; j++) { if (table_receptacle[i] == table_adapter[j].second) { addEdge(device + receptacle + j, device + i,1); } } } for (int i = 1; i <= adapter; i++) { for (int j = 1; j <= adapter; j++) { if (i == j) { continue; } if (table_adapter[i].first == table_adapter[j].second) { addEdge(device + receptacle + j, device + receptacle + i,infinity); } } } } void getMaxFlow() { vector<int>path(vexnum); while (1) { vector<int>augument(vexnum); queue<int>Q; Q.push(src); augument[src] =infinity; while (!Q.empty()) { int x = Q.front(); Q.pop(); for (unsigned int i = 0; i < adjList[x].size(); i++) { Edge&e = edge[adjList[x][i]]; if (!augument[e.to]&&e.capacity>e.flow) { path[e.to] = adjList[x][i]; augument[e.to] = std::min(augument[x],e.capacity-e.flow); Q.push(e.to); } } if (augument[sink]) { break; } } if (!augument[sink]) { break; } for (int u = sink; u!=src; u=edge[path[u]].from) { edge[path[u]].flow += augument[sink]; edge[path[u]^1].flow-= augument[sink]; } max_flow += augument[sink]; } } void print() { cout << device-max_flow << endl; count++; } int main() { #ifdef T freopen("in.txt","r",stdin); freopen("out.txt","w",stdout); #endif // T int n; cin >> n; while (n--) { init(); network(); getMaxFlow(); print(); if (n) { cout << endl; count++; } } return 0; }
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原文地址:http://blog.csdn.net/xf_zhen/article/details/51367469