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Time Limit: 1MS | Memory Limit: 102400KB | 64bit IO Format: %I64d & %I64u |
Description
Input
Output
Sample Input
input | output |
---|---|
abbbba |
111111 |
Source
#include <iostream> #include <string.h> #include <stdlib.h> #include <math.h> #include <stdio.h> using namespace std; typedef long long int LL; const int MAX=5*1e6; const int maxn=4*1e6+5; char str[MAX+5]; struct Tree { int next[maxn][2]; int fail[MAX+5]; int len[MAX+5]; int s[MAX+5]; int last,n,p; int new_node(int x) { memset(next[p],0,sizeof(next[p])); len[p]=x; return p++; } void init() { p=0; new_node(0); new_node(-1); last=0;n=0; s[0]=-1; fail[0]=1; } int get_fail(int x) { while(s[n-len[x]-1]!=s[n]) x=fail[x]; return x; } int add(int x) { x-='a'; s[++n]=x; int cur=get_fail(last); if(!(last=next[cur][x])) { int now=new_node(len[cur]+2); fail[now]=next[get_fail(fail[cur])][x]; next[cur][x]=now; last=now; return 1; } return 0; } }tree; char ans[MAX+5]; int main() { while(scanf("%s",str)!=EOF) { tree.init(); int i; for( i=0;str[i];i++) { if(!tree.add(str[i])) ans[i]='0'; else ans[i]='1'; } ans[i]='\0'; puts(ans); } return 0; }
URAL 2040 Palindromes and Super Abilities 2(回文树)
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原文地址:http://blog.csdn.net/dacc123/article/details/51360205