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LintCode:空格替换

时间:2016-05-12 16:03:46      阅读:123      评论:0      收藏:0      [点我收藏+]

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LintCode:空格替换

注意事项

如果使用 Java 或 Python, 程序中请用字符数组表示字符串。

Python

方法一:这个方法没有使用字符数组,直接使用的字符串数组,虽然能通过,但是不符合要求,看方法2吧。

class Solution:
    # @param {char[]} string: An array of Char
    # @param {int} length: The true length of the string
    # @return {int} The true length of new string
    def replaceBlank(self, string, length):
        # Write your code here
        if string == None:
            return 0
        while ‘ ‘ in string:
            m = string.index(‘ ‘)
            string[m] = ‘%20‘
            length += 2
        return length

方法二:

class Solution:
    # @param {char[]} string: An array of Char
    # @param {int} length: The true length of the string
    # @return {int} The true length of new string
    def replaceBlank(self, string, length):
        # Write your code here
        if string == None:
            return 0
        while ‘ ‘ in string:
            m = string.index(‘ ‘)
            n = length
            length = length + 2
            while n > m:
                string[n+2] = string[n]
                n -= 1
            string[m] = ‘%‘
            string[m+1] = ‘2‘
            string[m+2] = ‘0‘
        return length

Java

public class Solution {
    /**
     * @param string: An array of Char
     * @param length: The true length of the string
     * @return: The true length of new string
     */
    public int replaceBlank(char[] string, int length) {
        // Write your code here
        if (length == 0){
            return 0;
        }
        while(contains(string)){
            int m = index(string);
            int n = length;
            length = length + 2;
            while(n > m){
                string[n + 2] = string[n];
                n -= 1;
            }
            string[m] = ‘%‘;
            string[m+1] = ‘2‘;
            string[m+2] = ‘0‘;
        }
        return length;
    }

    private static boolean contains(char[] string){
        for(int i=0; i<string.length; i++ ){
            if(string[i] == ‘ ‘){
                return true;
            }
        }
        return false;
    }

    private static int index(char[] string){
        for(int i=0; i<string.length; i++){
            if(string[i] == ‘ ‘){
                return i;
            }
        }
        return 0;
    }
}

LintCode:空格替换

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原文地址:http://blog.csdn.net/u012225151/article/details/51367164

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